Comments on: Linq to XML Tutorial

By: Joe

Joe — Thu, 26 Jan 2012 23:12:13 +0000

Snehal

Are you using the exact code from the post? Would need to see what line your getting the error on to give any help. Also, am assuming the error is ‘Object reference not set to an instance of an object”?

It’s possible that the element your trying to access doesn’t exist.

Joe

By: Snehal

Snehal — Wed, 25 Jan 2012 11:08:37 +0000

It is good.
I am getting error, while updating the thing, data in xml file is getting updated but while fetching it again I am getting “Object reference not set to null”. Can anyone help?

By: JOJY

JOJY — Mon, 09 Jan 2012 07:26:56 +0000

GOOD TUTORIAL FOR BEGINNERS…THANKS A LOT

By: Rahul

Rahul — Fri, 30 Dec 2011 01:11:35 +0000

Thank you for taking the time to write such a clear and concise article on Linq to XML for the benefit of all.

By: kellsie

kellsie — Thu, 22 Dec 2011 10:50:48 +0000

thanks a lots.good article for beginners.

By: Charles

Charles — Thu, 01 Dec 2011 09:08:38 +0000

Thanks for this post. Helped me a lot

By: August Duet

August Duet — Thu, 10 Nov 2011 10:12:44 +0000

Thanks Joe, After several hours and some ugly code that only marginally worked this article cleared it all up for me. Keep it up.

By: KinQ

KinQ — Wed, 19 Oct 2011 13:16:00 +0000

Awesome tutorial/example
thanks a lot

By: Jatin Chadarana

Jatin Chadarana — Mon, 12 Sep 2011 17:37:07 +0000

Great Article for beginner….

By: Mangrish Naik

Mangrish Naik — Thu, 18 Aug 2011 12:51:08 +0000

It ws very helpful tutorial…..
learned a lot 4m examples

By: Thottijeya

Thottijeya — Wed, 11 May 2011 06:47:25 +0000

Useful article! You deserve lot of thanks for your spending time on helping us learn the basics of LINQ to XML. This article is a nice introduction to those who want to start learning LINQ to XML.

By: Joe

Joe — Thu, 28 Apr 2011 00:07:43 +0000

Hi Pranshu

It’s difficult to say what your issue is without seeing all your code.

Cheers
Joe

By: Pranshu

Pranshu — Wed, 20 Apr 2011 10:14:37 +0000

Hi Joe,

It was a nice post. I am new to Linq.
However while tying your given code in POC (VS2010); I was geting null exception on below lines:
c.Attribute(“ID”)Value.Equals(customerID.ToString())
and
c.Element(“Forename”).Value
also on all similar lines.

While debugging I was able to rectify the issue by replcaing it to:
c.Element(“Customer”).Attribute(“ID”).Value.Equals(customerID.ToString())
and
c.Element(“Customer”).Element(“Forename”).Value

I was confused to see so many comments on the post and none of us faced such issue.

You can mail me for further clarification/information.

Please correct me know in case I have missed out anything or interpreted wrongly.

Regards,
Pranshu

By: Ik0_a

Ik0_a — Mon, 28 Mar 2011 15:07:59 +0000

Good article to begin with.

Thank !

By: Yehuda

Yehuda — Fri, 11 Mar 2011 23:16:20 +0000

Excellent!
Thank you.

By: Ian

Ian — Sat, 05 Feb 2011 11:56:17 +0000

Is there a bug in the GetCustomers() method in the orderby clause? I reckon that “Surname” is an Element not an Attribute and I also reckon that you would have to tack a .Value onto the end.

i.e. I think the orderby clause should be:
orderby c.Element(“Surname”).Value

By: var

var — Sun, 12 Dec 2010 19:14:58 +0000

Thanks. This was a great help.

What would the save method look like, if each customer had a repeating sub element?

555-1212
555-1111
555-2121

By: Kas

Kas — Sat, 11 Dec 2010 04:42:38 +0000

Hi Joe,

Thank you for this article. It was very helpful for me.

Regards,
Kas

By: Piotr

Piotr — Sun, 21 Nov 2010 21:39:24 +0000

Hi i just used your class GetNextAvailableID() and when id reached 10, next avalible id was 2, i just delete FirstOrDefault from:
select c.Attribute(“ID”).Value).FirstOrDefault()
and it works fine, anyway this article help me a lot:) (I’m newbie to linqtoxml and c#)

By: Anand K Reddy

Anand K Reddy — Thu, 18 Nov 2010 00:44:04 +0000

Superab!!!

It has made my job very easy to get started on Linq to xml.

Thank you

By: Kapil

Kapil — Tue, 09 Nov 2010 02:30:11 +0000

Hi,

Nice article, I am doing similar thing but i want to select the Phone based on Type (attribute)

some thing like this

XXX-XXX-XXXX
XXX-XXX-XXXX

So i can do the if inside the Select new Customer()
{
PhoneHome = ????
}

can you help me on that? Thanks

By: Noman A. Siddiqui

Noman A. Siddiqui — Wed, 27 Oct 2010 13:24:11 +0000

Great Article…. Thanks Joe.

By: cipher0003

cipher0003 — Fri, 08 Oct 2010 08:33:36 +0000

Great example!! Thanks for sharing!! I wonder, that there is nothing comparable out there.
I found very strange to see a copy of your article.
Community means sharing and make it even better, not plain copying…….

By: Joe

Joe — Tue, 31 Aug 2010 03:59:09 +0000

Ralph

It’s just a POCO. I can’t really help without knowing exactly where you are getting your exception or seeing the source code.

Joe

By: Ralph Daudi

Ralph Daudi — Fri, 27 Aug 2010 11:26:40 +0000

Hi Joe

It is basically the same code as yours, but was trying to understand it by building from scratch – are you using Reflection for the Customer class?